Given a parallelogram ABCD, $a r (A B C D) = 50 m^{2}, C H ⊥ E D$ . If $C H = 5 m$ , find $E D .$

10 m

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5 m

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20 m

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25 m

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Solution

The correct option is A $10 m$
$a r (E D C) = \frac{1}{2} a r (A B C D)$
$= \frac{1}{2} \times 50 = 25 m^{2}$
Now, $a r (E D C) = \frac{1}{2} \times C H \times E D$
$\Rightarrow 25 = \frac{1}{2} \times 5 \times E D$
$\Rightarrow E D = 10 m$

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Given a parallelogram ABCD, ar(ABCD)=50 m2,CH⊥ED. If CH=5 m, find ED.

The correct option is A 10 mar(EDC)=12ar(ABCD)=12×50=25 m2Now, ar(EDC)=12×CH×ED⇒25=12×5×ED⇒ED=10 m

Given a parallelogram ABCD, $a r (A B C D) = 50 m^{2}, C H ⊥ E D$ . If $C H = 5 m$ , find $E D .$

The correct option is A $10 m$
$a r (E D C) = \frac{1}{2} a r (A B C D)$
$= \frac{1}{2} \times 50 = 25 m^{2}$
Now, $a r (E D C) = \frac{1}{2} \times C H \times E D$
$\Rightarrow 25 = \frac{1}{2} \times 5 \times E D$
$\Rightarrow E D = 10 m$