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Triangular Matrix

Given, A = ...

Question

Given, $A = {$ Quadrilaterals $}$ , $B = {$ Rectangles $}$ , $C = {$ Squares $}$ , $D = {$ Rhombuses $}$ . explain, giving reasons, if $D \subset$ $B$ or not.

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Solution

$A = {Q u a d r i l a t e r a l}$
$B = {R e c t a n g l e}$
$C = {S q u a r e s}$
$D = {R h o m b u s}$
In a rectangle , opposite sides and opposite angles are equal. All angles are $90^{o}$ then $D$ is not a subset of $B$ .
So, $D \subset̸ B$

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A = {Q u a d r i l a t e r a l s}, B = {R e c t a n g l e s}, C = {S q u a r e s} D = {R h o m b u s e s}

B \subset C (i i) D \subset B (i i i) C \subseteq B \subseteq A (i v) D \subset A (v) B \supseteq C (v i) A \supseteq B \supseteq D

Give reasons for the following:

(a) A square can be thought of as a special rectangle.

(b) A rectangle can be thought of as a special parallelogram.

(d) Squares, rectangles, parallelograms are all quadrilaterals.

(e) Square is also a parallelogram.

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