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Question

Given a reaction:
Cr2O2−7+XH⊕−−−−−−→Cr3++H2O + oxidised product of X.
X in the above reaction cannot be :

A
C2O24
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B
Fe2+
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C
SO24
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D
S2
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Solution

The correct option is B SO24
Cr2O27+XH−−−−−Cr3++H2O + oxidised product of X.
X in the above reaction cannot be SO24 as SO24 contains S in the highest oxidation state (+6) and cannot be oxidized further.

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