Given a rectangle ABCD and P,Q,R,S mid-points of AB,BC,CD and DA respectively. If length of diagonal of rectangle is 8 cm , the quadrilateral PQRS is
A
Parallelogram with adjacent sides 4 cm and 8 cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Rhombus with side 4 cm
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
Rectangle with adjacent sides 4 cm and 8 cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Square with side 4 cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is BRhombus with side 4 cm
The figure PQRS, formed by joining the mid points of the adjacent sides of a rectangle ABCD is a rhombus. In ΔBCD, the points Q and R are mid points sides BC and CD respectively. ∴QR||DB (By mid-point theorem) QR=12DB QR=12(8) QR=4 Hence, it is rhombus with side 4 cm.