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Question

Given a=sec2α,b=cosec2α,and,c=11sin2αcos2α. If tan3αtanα=λab,then λ=

A
3b443a
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B
43a3b4
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C
3b+44+3a
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D
4+3a3b+4
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Solution

The correct option is A 3b443a

tan3α=sin3αcos3α=3sinα4sin3α4cos3α3cosα=tanα(34sin2α4cos2α3)
=tanα(34b)(4a3)=tanα(3b443a)ab
Hence λ=3b443a


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