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Question

Given a solution of acetic acid. How many times of the acid concentration, acetate salt should be added to obtain a solution with pH=7?
Ka for dissociation of CH3COOH=1.8×105.

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Solution

Acetate salt and acetic acid will form an acidic buffer.
So for an acidic buffer pH=pKa+log[Salt][Acid]
pH=pKa+log[Acetate salt][Acetic Acid]
7=5log(1.8)+log[Acetate salt][Acetic Acid]
7=4.75+log[Acetate salt][Acetic Acid]
2.25=log[Acetate salt][Acetic Acid]
[Acetate salt][Acetic acid]=179.9

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