Given a triangle ABC in which ∠B > ∠C then
AB > AC
AC > BC
AB = AC
AC > AB
∠B > ∠C, hence AC > AB (side opposite the greater angle is longer.)
△ ABC, right angled at B, ∠ACB = 60∘, expressions for sec 60 and cosec 60 is
In drawing triangle ABC, it is given that AB = 3 cm, BC = 2 cm and AC = 6 cm. It is not possible to draw the triangle as:
In any triangle ABC, (AB - AC) > BC.
In a triangle ABC, if AC2 + BC2 = AB2, then which of the following sides are perpendicular?