Given a uniform electric field $E = 5 \times 10^{3}^i N / C$ . Find the flux of this field through a square of side $10 c m$ on a side whose plane is parallel to YZ-plane :

5 N m^{2} / C

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25 N m^{2} / C

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50 N m^{2} / C

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500 N m^{2} / C

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Solution

The correct option is C $50 N m^{2} / C$
the vector $^i$ shows that the field is parallel to the X axis
The square being parallel to the YZ-plane is perpendicular to the field.
Hence flux will be the product of the area of the square and the field.
Flux= $5 \times 10^{3} \times 0.1 \times 0.1$ because $10 c m = 0.1 m$ and area of square = $s i d e^{2}$

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Given a uniform electric field E=5×103^iN/C. Find the flux of this field through a square of side 10cm on a side whose plane is parallel to YZ-plane :

Given a uniform electric field $E = 5 \times 10^{3}^i N / C$ . Find the flux of this field through a square of side $10 c m$ on a side whose plane is parallel to YZ-plane :