Given a uniform electric field $E = 5 \times 10^{3}^i N / C$ . What would be the flux through the same square if the plane makes an angle of $30^{o}$ with the x-axis?

5 N m^{2} / C

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25 N m^{2} / C

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50 N m^{2} / C

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500 N m^{2} / C

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Solution

The correct option is B $25 N m^{2} / C$
flux is the dot product between the area vector and the field vector.
Area vector is perpendicular to the surface. If the surface makes an angle $30^{o}$ with the YZ_plane, then the angle between the area vector and field vector will be $60^{o}$
So, flux $= E A c o s 60 = 50 \times \frac{1}{2} = 25$

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