The correct option is D The velocity of wave is not same in both the strings.
When a wave travels in a string with different density, it gets partly reflected and partly transmitted.
The formula for amplitude of a reflected wave while the wave is travelling from one medium to the other is given by,
Ar=√μr−√μi√μi+√μr×A
μi: Linear mass density of 1st string
μr: Linear mass density of second string
Ar: Amplitude of reflected wave.
Let μi=μ,
Given that, μr=4μ
⇒Ar=√4μ−√μ√4μ+√μ×A
⇒Ar=A3
The amplitude of the transmitted wave is given by,
At=2√μi√μi+√μt×A
⇒At=2√μ√μ+2√μA=2A3
The velocity of the wave in a string is given by,
Vw=√Tμ
As, the tension in both the string is same, and μ is more for second string, the velocity of the wave are unequal in both the strings.
Hence, A,B and D are correct.