Given A - x - x - N and 3 - x - 6 and B - x - x - W and x - 4- then find - A - B-

A={ x:x∈ N,3 lt;x≤ 6 } ∴ A={ 4,5,6 } B={ x:x∈ W,x lt;4 } ∴ B={ 0,1,2,3 } [ x∈ W i.e., Whole Number] A∪ B= contains all the el ...

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Byju's Answer

Standard XII

Mathematics

Union

Given A = x...

Question

Given A = { $x$ : $x \in N$ and $3 < x \leq 6$ } and B = { $x$ : $x \in W$ and $x < 4$ }, then find : A $\cup$ B.

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Solution

$A = {x : x \in N, 3 < x \leq 6}$

$∴ A = {4, 5, 6}$
$B = {x : x \in W, x < 4}$

$∴ B = {0, 1, 2, 3}$ [ $x \in W$ i.e., Whole Number]
$A \cup B =$ contains all the elements of $A$ and $B$ But elements are not repeated.

$∴ A \cup B = {0, 1, 2, 3, 4, 5, 6}$

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Given A = {x : x∈N and 3<x≤6} and B = {x : x∈W and x<4}, then find : A ∪ B.

A={x:x∈N,3<x≤6}∴A={4,5,6}B={x:x∈W,x<4}∴B={0,1,2,3} [x∈W i.e., Whole Number]A∪B= contains all the elements of A and B But elements are not repeated.∴A∪B={0,1,2,3,4,5,6}

Given A = { $x$ : $x \in N$ and $3 < x \leq 6$ } and B = { $x$ : $x \in W$ and $x < 4$ }, then find : A $\cup$ B.

$A = {x : x \in N, 3 < x \leq 6}$

$∴ A = {4, 5, 6}$
$B = {x : x \in W, x < 4}$

$∴ B = {0, 1, 2, 3}$ [ $x \in W$ i.e., Whole Number]
$A \cup B =$ contains all the elements of $A$ and $B$ But elements are not repeated.

$∴ A \cup B = {0, 1, 2, 3, 4, 5, 6}$