Given ABCD is the parallelogram- if the value of DCE - X - then the value of BAD isA- X-B- 180-X-C -2 X -D- X - 2-

The correct option is B 180° X° ∠ BCD + ∠ DCE = 180^∘ sum of angles on a straight line) ∠ BAD = ∠ BCD (opposite angles in a parallelogram) ∠ BAD = 180^∘ X^∘ ...

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Standard VIII

Mathematics

Square

Given ABCD is...

Question

Given ABCD is the parallelogram, if the value of DCE = $X^{\circ}$ , then the value of BAD is

X°

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180°- X°

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2X°

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(X/2)°

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Solution

The correct option is B
180°- X°

$∠ B C D + ∠ D C E = 180^{\circ}$ sum of angles on a straight line)
$∠ B A D = ∠ B C D$ (opposite angles in a parallelogram)
$∠ B A D = 180^{\circ} - X^{\circ}$

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Given ABCD is the parallelogram, if the value of DCE = X∘, then the value of BAD is

The correct option is B 180°- X° ∠BCD+∠DCE=180∘ sum of angles on a straight line) ∠BAD=∠BCD (opposite angles in a parallelogram) ∠BAD=180∘−X∘

Given ABCD is the parallelogram, if the value of DCE = $X^{\circ}$ , then the value of BAD is

The correct option is B
180°- X°

$∠ B C D + ∠ D C E = 180^{\circ}$ sum of angles on a straight line)
$∠ B A D = ∠ B C D$ (opposite angles in a parallelogram)
$∠ B A D = 180^{\circ} - X^{\circ}$