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Question

Given AC circuit can be purely resistive if

A
Frequency w = 0
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B
Frequency w=1LCR2L2
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C
If R>LC
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D
Given circuit can never be purely resistive.
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Solution

The correct option is B Frequency w=1LCR2L2
1z=1z1+1z2=1wLj+R+11jwc
1z=RwLjR2+w2L2+jwc
For pure resistive circuit wc=wLR2+w2L2
So w2=1LCR2L2w2=1L2(LCR2)

So, there exists a real value of w which satisfies this equation when LC>R2.

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