Question

Given AE = 5 units, BD = 16 units and CF = 4 units. Find the area of quadrilateral ABCD.

Answer 1

Area of quadrilateral can be written as
Ar $\Delta$DAB + Ar $\Delta$DCB

= $\frac{1}{2}$ $\times 16$$\times 5$ $+\frac{1}{2}$$\times 16$ $\times 4$
= $\frac{1}{2}\times 16\times (5+4)$
= $8\times (5+4)$
= 72 sq. units