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Question

Given alongside is the velocity-tine graph for a moving body :

Figure

Find : (i) Velocity of the body at point C.
(ii) Acceleration acting on the body between A and B.
(iii) Acceleration acting on the body between B and C.

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Solution

(i) BC represents uniform velocity. So velocity of the body at point C is 40 km
(ii) Acceleration = Slope of line AB
=(40-20)(3-0)km/hr2=6.66 km/hr2
(iii) BC represents uniform velocity, so, acceleration acting on the body is zero.

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