Question

# Given an A.P. of common difference 6 and sum of n terms of the A.P. is given as an2+bn where a and b are constants. Find the value of 'a'.

A
12
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B
8
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C
6
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D
3
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Solution

## The correct option is D 3Let the first term of the given A.P. be 'a'. Sum of n terms of an A.P. with first term 'a' and common difference 'd' =n2[2a+(n−1)d] Given common difference of the A.P = 6 Sum of 'n' terms of the given A.P =n2[2a+(n−1)6]=n2[2a+6n−6]=n[a+3n−3]=3n2+(a−3)n

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