CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
Question

Given an A.P. of common difference 6 and sum of n terms of the A.P. is given as an2+bn where a and b are constants. Find the value of 'a'.

A
12
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
8
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
6
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 3
Let the first term of the given A.P. be 'a'.
Sum of n terms of an A.P. with first term 'a' and common difference 'd' =n2[2a+(n1)d]
Given common difference of the A.P = 6
Sum of 'n' terms of the given A.P =n2[2a+(n1)6]=n2[2a+6n6]=n[a+3n3]=3n2+(a3)n

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Arithmetic Progression
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon