(i)
Let A={5,6,7}
Define a relation R on A as R={(5,6),(6,5)}
Relation R is not reflexive as (5,5),(6,6),(7,7)∉R.
Now, as (5,6)∈R and also (6,5)∈R, R is symmetric.
⇒(5,6),(6,5)∈R, but (5,5)∉R
∴R is not transitive.
Hence, relation R is symmetric but not reflexive or transitive.
(ii)
Consider a relation R in R defined as
R={(a,b):a<b}
For any a∈R, we have (a,a)∉R since a cannot be strictly less than a itself. In fact, a=a.
∴R is not reflexive.
Now, (1,2)∈R(as1<2)
But, 2 is not less than 1.
∴(2,1)∉R
∴R is not symmetric.
Now, let (a,b),(b,c)∈R.
⇒a<b and b<c
⇒a<c
⇒(a,c)∈R
∴R is transitive.
Hence, relation R is transitive but not reflexive and symmetric.
(iii)
Let A={4,6,8}
Define a relation R on A as:
A={(4,4),(6,6),(8,8),(4,6),(6,4),(6,8),(8,6)}
Relation R is reflexive since for every {a∈A,(a,a)∈Ri.e.,(4,4),(6,6),(8,8)}∈R
Relation R is symmetric since (a,b)∈R⇒(b,a)∈R for all a,b∈R.
Relation R is not transitive since (4,6),(6,8)∈R, but (4,8)∉R.
Hence, relation R is reflexive and symmetric but not transitive.
(iv)
Define a relation R in R as:
R={(a,b):a3≥b3}
Clearly (a,a)∈R as a3=a3.
∴R is reflexive.
Now, (2,1)∈R (as23≥13)
But, (1,2)∉R(as13<23)
∴R is not symmetric.
Let (a,b),(b,c)∈R
⇒a3≥b3 and b3≥c3
⇒a3≥c3
⇒(a,c)∈R
∴R is transitive.
Hence, relation R is reflexive and transitive but not symmetric.
(v)
Let A={−5,−6}.Define a relation R on A as:R={(−5,−6),(−6,−5),(−5,−5)}Relation R is not reflexive as (−6,−6)∉RRelation R is symmetric as (−5,−6)∈R and (−6,−5)∈RIt is seen that (−5,−6),(−6,−5)∈R. Also, (−5,−5)∈R.
∴ the relation R is transitive.
Hence, relation R is symmetric and transitive but not reflexive.