Given are two tuning forks near one another, one of them is of unknown frequency and the other is of frequency 591Hz. We can hear beats of maximal intensity I0,5 times each second. Then -
A
Unknown frequency may be 596Hz
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B
Unknown frequency may be 586Hz
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C
Difference in frequency of two tuning forks is 5Hz
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D
Intensity at time t = 2720sec isI02
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Solution
The correct options are A Unknown frequency may be 596Hz B Unknown frequency may be 586Hz C Difference in frequency of two tuning forks is 5Hz D Intensity at time t = 2720sec isI02 Beat frequency : f1−f2=±5 ⇒f1=f2±5 f1=f2+5orf1=f2−5 f1=596orf1=586Hz Intensity : I=I0cos2(ω1t−ω2t2) where f = frequency I = intensity I0 = maximum intensity =I0cos22π2(f1−f2)t =I0cos2(π×5×2720) =I0cos23π4=I02