Given: Area of parallelogram = Base × Height
Statement 1: A diagonal of a parallelogram divides it into two congruent triangles.
Statement 2: Areas of two congruent triangles are exactly equal
Both the statements are true and enough to determine area of a triangle
Area of parallelogram = Base × Height
In ∆ABD and ∆CDB,
AB = CD (Opposite sides of a parallelogram)
AD = BC (Opposite sides of a parallelogram)
BD = DB (Common)
∆ABD ≅ ∆CDB [By SSS congruence condition]
So, statement 1 is true.
Also, two figures are said to be congruent if they have exactly same shape and size. This means that they have equal area. Hence, two congruent triangles will have equal areas but the converse may not be true. Statement 2 is also correct.
From the two statements, we can say that
Area (∆ABD) + Area (∆CDB) = Area (parallelogram ABCD)
2. Area (∆ABD) = Base × Height
Area (∆ABD) = (1/2) × Base × Height
Hence, both the statements are correct and enough to determine the area of a triangle