Question

Given Arithmetic Progression $12,16,20,24,....$. Find the ${24}^{th}$ term of this progression.

Answer 1

The A.P. $12,16,20,24$
Here $a=12,d=16-12=4,t_{24}=?$
$t_n=a+(n-1)d$
$\therefore t_{24}=12+(24-1)4$ $(\because n=24)$
$=12+23\times 4$
$=12+92$
$\therefore t_{24}=104$
Thus ${24}^{th}$ term of the A.P. is $104$.