Question

Given Arithmetic Progression 12, 16, 20, 24, . . . Find the 24^th term of this progression.

Answer 1

The given sequence is 12, 16, 20, 24, . . .

Here,
First term (a) = 12

Common difference (d) = a₂ – a₁ = 16 – (12) = 4

Now,
$$\begin{gathered} a_{24}=a+\left(n-1\right)d \\ =12+\left(24-1\right)4 \\ =12+\left(23\right)4 \\ =104 \end{gathered}$$

Hence, the 24^th term of the progression is 104.