Given, BC = 5 cm and the corresponding altitude AP = 8 cm. Find the area of the parallelogram ABCD.

[2 Marks]

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Solution

Area of the parallelogram ABCD = $(b a s e \times h e i g h t)$
= $B C \times A P$ [1 Mark]

= $8 \times 5$

= $40 c m^{2}$ [1 Mark]

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