The correct option is A The measure of the center for data 1 is less than that of data 2, and the variation for data 1 is less than that of data 2.
Data 1:
Measure of center, median =42
IQR = Third quartile − First quartile =50−40=10
Data 2:
Measure of center, median =50
IQR = Third quartile − First quartile =65−45=20
So, we can say that the measure of the center for data 1 is less than that of data 2, and the variation for data 1 is less than that of data 2.