wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Given below are the standard electrode potentials of a few half-cells. K+/K=-2.93V,Ag+/Ag=0.80V,Mg2+/Mg=2.37V,Cr3+/Cr=0.74V. What will be the correct order of these metals in increasing reducing power?


Open in App
Solution

Redox potential

  • Redox potential is a measure of tendency of chemical species to get reduced or oxidised by gaining or losing electrons to an electrode.

Reducing power

  • Reducing power is the potential of a substance to reduce another substance.
  • More the oxidation potential the element will have more tendency to get oxidised.
  • Reduction potential of half cells are:

K+/K=-2.93VAg+/Ag=0.80VMg2+/Mg=2.37VCr3+/Cr=0.74V

  • The more easily it removes electrons or higher the reduction potential higher is its reducing power, the more it will reduce other substance.
  • Order of these metals in increasing reducing powers is Ag<Cr<Mg<K.

Therefore, potassium has lowest reduction potential, therefore, it can donate electrons easily and reduces other substance.


flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Electrochemical series_tackle
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon