You visited us 4 times! Enjoying our articles? Unlock Full Access!

Le Chatelier's Principle for Del N Greater Than Zero

Given below a...

Question

Given below are two reversible reactions :
$A + B ⇌ Z$ ; $K_{c_{1}} = 24$
$2 B + C ⇌ 2 Y$ ; $K_{c_{2}} = 16$
The equilibrium constant $K_{c}$ for the reaction :
$A + Y ⇌ Z + \frac{C}{2}$ is

Open in App

Solution

$A + B ⇌ Z$ ; $K_{c_{1}} = 24$ ......(1)
$2 B + C ⇌ 2 Y$ ; $K_{c_{2}} = 16$ ......(2)
The reaction 2 is reversed and divided by 2 to obtain
$Y ⇌ B + \frac{1}{2} C$ ; $K_{c_{3}} = \frac{1}{\sqrt{K_{c_{2}}}} = \frac{1}{\sqrt{16}} = \frac{1}{4}$ ......(3).
The reactions (1) and (3) are added to obtain the reaction (4).
$A + Y ⇌ Z + \frac{C}{2}$ ......(4)
The equilibrium constant $K_{c}$ for the reaction
(4) is
$K_{c_{4}} = K_{c_{1}} \times K_{c_{3}} = 24 \times \frac{1}{4} = 6$ .

Suggest Corrections

Similar questions

S (s) + O_{2} (g) ⇌ {S O}_{2} (g); K_{c 1} = 5 \times 10^{52}

2 S (s) + 3 O_{2} (g) ⇌ 2 S O_{3} (g); K_{c 2} = 10^{29}

K_{c}

2 {S O}_{2} (g) + O_{2} (g) ⇌ 2 S O_{3} (g)

A + B ⇌ E; K_{c} = 6

2 B + C ⇌ 2 D; K_{c} = 4

K_{c}

A + D ⇌ E + \frac{1}{2} C

A + 2 B ⇌ 2 C

C ⇌ B + 1 / 2 A

2 N O + O_{2} ⇌ 2 N O_{2}

K_{C_{1}}

N O_{2} + S O_{2} ⇌ S O_{3} + N O

K_{C_{2}}

2 S O_{3} ⇌ 2 s O_{2} + O_{2}

K_{C_{3}}

K_{p}

K_{c}

Join BYJU'S Learning Program