CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R.

Assertion A: Body P having mass M moving with speed ‘u’ has head-on collision elastically with another body ‘Q’ having mass ‘m’ initially at rest. If m<<M, body ‘Q’ will have a maximum speed equal to ‘2u’ after collision.

Reason R: During elastic collision, the momentum and kinetic energy are both conserved.

In the light of the above statements, choose the most appropriate answer from the options given below:


A

A is correct but R is not correct.

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

Both A and R are correct but R is NOT the correct explanation of A

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

A is not correct but R is correct.

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

Both A and R are correct and R is the correct explanation of A.

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D

Both A and R are correct and R is the correct explanation of A.


Step 1. Given data :

The mass of a bodyP is M.

The mass of a body Q ism.

Where m<<M.

The velocity of bodyP is u before the collision

Step 2. Solving for the maximum velocity of Q after collision

An elastic collision is a collision in which there is no net loss in kinetic energy in the system as a result of the collision.

Both momentum and kinetic energy are conserved quantities in elastic collisions.

From momentum conservation, second body at rest initially we have

m1v1=m1v'1+m2v'2

Kinetic energy we have12m1v21=12m1v'21+12m2v'22

The velocity of second body after collision

v2'=2m1m1+m2v1v2'=2MM+mu

now since M>>m, we have

v2'=2MMu=2u

Where M is mass of Body P having with initial velocity u and body ‘Q’ having mass ‘m’ initially at rest. After collision body P have velocity v'1 and body Q have velocity v2' .

So, From conservation of momentum and kinetic energy equation was derived which gave velocity of second particle after collision to be 2u. So, both the assertion and reason are correct and reason explains the assertion.

Hence, option D is correct.


flag
Suggest Corrections
thumbs-up
7
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
A No-Loss Collision
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon