Question

Given below id the reaction involved in the manufacture of ammonia:

$N_2\left(g\right)+3H_2\left(g\right)\rightleftharpoons 2{\mathrm{NH}}_3\left(g\right)$

If 2 moles of nitrogen and 6 moles of hydrogen were made to react instead, how many moles of ammonia will be produced?

• A. 4

Answer 1

The correct option is A 4
According to the reaction,

$N_2\left(g\right)+3H_2\left(g\right)\rightleftharpoons 2{\mathrm{NH}}_3\left(g\right)$

1 mole of nitrogen reacts with 3 moles of hydrogen to produce 2 moles of ammonia. So, if 2 moles of nitrogen were to react with 6 moles of hydrogen, 4 moles of ammonia will be produced.