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Question

Given below is a balanced chemical reaction for the formation of ammonia.

N2(g)+3H2(g)2NH3(g)

Estimate the volume of hydrogen gas required to produce 44.8 litres of NH3. (Assume the reaction takes place at STP)

A
22.4 L
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B
67.2 L
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C
44.8 L
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D
11.2 L
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Solution

The correct option is B 67.2 L
The given chemical equation is balanced:

N2(g)+3H2(g)2NH3(g)

At STP, moles of gas = Volume at STPMolar volume

Moles of NH3 produced = 44.822.4=
2 moles.
From the given chemical equation, 2 moles of NH3 are produced from 3 moles of H2
Volume of hydrogen gas required = Moles × Molar volume at STP
Volume of hydrogen gas required = 3 × 22.4 = 67.2 litres.

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