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Question

Given below is sequence of the processed mRNA ready for translation
5' AUG CUA UAC UAA CUG CCA UGC UAG 3'
How many amino acids will present in polypeptide chain corresponding to this mRNA?

A
7
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B
8
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C
6
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D
3
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Solution

The correct option is D 3
Proteins are made up from a set of 20 amino acids called standard amino acids. A three letter code of nucleotides called codon specify for amino acids. Polypeptide synthesis proceeds from a N-terminus to C-terminus and ribosome reads mRNA in the 5' to 3' direction. Three kinds of RNA molecules perform different but cooperative functions in protein synthesis. mRNA carries the genetic information copied from DNA in the form of a series of these three letter code words. There are in total 64 codons . Out of these, 61 codons code for amino acids whereas 3 codons donot code for any amino acid. These three codons UAA, UAG and UGA are termed as stop codons as when these are read by the ribosomes no amino acid is incorporated. Rather the protein synthesis terminates. Protein synthesis begins with codon termed as initiator codon generally AUG. In eukaryotes this codon codes for methionine whereas in prokaryotes this codes for N-formylmethione. Protein synthesis initiates with a initiator codon in the mRNA and terminates with the stop codon. In the given sequence there are eight codons. But since the fourth codon is UAA which is a stop codon the translation process will terminate there and a protein of 3 amino acids will be synthesized. All other options are hence incorrect and D is the correct answer.

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