Given below is the frequency distribution table regarding the concentration of sulphur dioxide in the air in parts per million of a certain city for 30 days.
Conc. of SO20.00−0.040.04−0.080.08−0.120.12−0.160.16−0.200.20−0.24No. of days489243
Find the probability of conentration of sulphur dioxide in the interval 0.12-0.16 on any of these days.
Total number of days (n)=30
Conc. of SO20.00−0.040.04−0.080.08−0.120.12−0.160.16−0.200.20−0.24No. of days489243
Probability of conc. of SO2 of the interval 0.12-0.16(m)=2
∴ Probability P(A) =mn=115