Question

Given $C_1=C_5=C_3=2\mu F,C_2=C_4=4\mu F$.
$2\mu F$ can withstand maximum voltage of $5V$ and $4\mu F$ can withstand maximum of $10V$. Which of the capacitors will burn?

• A. All
• B. $C_1$ and $C_2$
• C. $C_1$ and $C_5$
• D. $C_1,C_2$ and $C_5$

Answer 1

The correct option is C $C_1$ and $C_5$

$q_1=q_2=15\times \frac{8}{6}\Rightarrow V_1=\frac{q_1}{C_1}=\frac{15\times 8}{6\times 2}$
$=10V$ (will burn)
& $V_2=5V$ (will not burn)
$q_3+q_4=q_5=\frac{3}{2}\times 15=\frac{45}{2}$
$V_5=\frac{q_5}{C_5}=\frac{45}{2\times 2}=11.25V$(will burn)
$V_3=V_4=15-V_5=3.75V$ (will not burn)