Given -Cgraphite- 12O2 - CO - H1 - -110-5 kJ-molCO- 12O2 - CO2 - H - -283-2 kJ-molThe heat of reaction in kJ-mol for the following reaction is-Cgraphite- O2 - CO2 - H - -

The thermochemical reactions are given as: C(graphite)+ 12O_2 → nbsp; CO Δ H_1 = 110.5 kJ/mol CO+ 12O_2 → nbsp; CO_2 Δ H_2 = 283.2 kJ/mo ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Heat of Reaction

Given :Cgraph...

Question

Given :
$C (g r a p h i t e) + \frac{1}{2} O_{2} \to C O Δ H_{1} = - 110.5 k J / m o l$

$C O + \frac{1}{2} O_{2} \to C O_{2} Δ H = - 283.2 k J / m o l$

The heat of reaction (in $k J / m o l$ ) for the following reaction is:
$C (g r a p h i t e) + O_{2} \to C O_{2} Δ H = ?$

393.7

No worries! We‘ve got your back. Try BYJU‘S free classes today!

-393.7

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

-172.7

No worries! We‘ve got your back. Try BYJU‘S free classes today!

172.7

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

C

+ \frac{1}{2} O_{2} \to C O; Δ H = - 110.5

C O + \frac{1}{2} O_{2} \to C O_{2}; Δ H = - 283.2

C (graphite) + O_{2} \to C O_{2}

C (g r a p h i t e) + \frac{1}{2} O_{2} \to C O Δ H_{1} = - 110.5 k J / m o l

C O + \frac{1}{2} O_{2} \to C O_{2} Δ H = - 283.2 k J / m o l

k J / m o l

C (g r a p h i t e) + O_{2} \to C O_{2} Δ H = ?

From the thermo chemical reactions,

$C_{(g r a p h i t e)} + \frac{1}{2} O_{2} \to C O; Δ H = - 110.5 K J$

$C O + \frac{1}{2} O_{2} \to C O_{2}; Δ H = - 283.2 K J .$

$Δ H$ for the reaction, $C_{(g r a p h i t e)} + O_{2} \to C O_{2}$ is:

C_{(g r a p h i t e)} + \frac{1}{2} O_{2} \to C O; Δ H = - 110.5 k J

C O + \frac{1}{2} O_{2} \to {C O}_{2}; Δ H = - 283.2 k J

C_{(g r a p h i t e)} + O_{2} \to {C O}_{2}

From the thermochemical reactions,

C + 1/2O₂ → CO; ∆H = -110.5 kJ

CO + 1/2O₂→ CO₂; ∆H = -283.2 kJ

The heat of reaction C + O₂ → CO₂ is:

Join BYJU'S Learning Program

Explore more

Join BYJU'S Learning Program