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Question

Given: dE=TdS−pdV and H=E+pV.


Which one of the following relation is true?

A
dH=TdS+Vdp
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B
dH=SdT+Vdp
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C
dH=SdTVdp
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D
dH=dEpdV
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Solution

The correct option is A dH=TdS+Vdp
Given,

dE=TdSpdV ...(i)

H=E+pV ...(ii)

Differentiating Eq. (ii),we gte:

dH=dE+pdV+Vdp ...(iii)

From Eq. (i) and (iii), we get-

dH=Tds+Vdp

Hence, option A is correct.

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