Given, ΔABC∼ΔPQR.
Find the values of y and z.
y=3√3
y=4√3
z=6
z=4
Since ΔABC∼ΔPQR
∴3z=y4√3=68
∴3z=y4√3=34
When we take
∴3z=34
3z=12
And
y4√3=34
ΔABC∼ΔPQR
Let y = logakx, z = logax. Find the relation between y and z.