Given - ABC - PQR- if ABPQ - 13 then find ar- ABCar- PQR

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Given Δ ABC...

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Given $Δ A B C \sim Δ P Q R$ , if $\frac{A B}{P Q} = \frac{1}{3}$ then find $\frac{a r Δ A B C}{a r Δ P Q R}$

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Δ A B C \sim Δ P Q R,

\frac{A B}{P Q} = \frac{1}{3},

\frac{a r Δ A B C}{a r Δ P Q R}

Δ A B C

\sim

Δ P Q R

\frac{A B}{P Q} = \frac{1}{3}

\frac{a r Δ A B C}{a r Δ P Q R}

Δ A B C \sim Δ P Q R

\frac{B C}{Q R} = \frac{1}{3}

\frac{a r (Δ P Q R)}{a r (Δ A B C)}

Δ A B C \sim Δ Q R P, \frac{a r (Δ A B C)}{a r (Δ P Q R)} = \frac{9}{4}

\frac{20}{3} c m

Δ A B C \sim Δ P Q R

a r (Δ A B C) = 4 a r (Δ P Q R)

B C = 12 c m,

Q R

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