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Question

Given b+c11=c+a12=a+b13 for a ΔABC with usual notation. If cosAα=cosBβ=cosCγ, then the ordered triad (α,β,γ) has a value:-

A
(3,4,5)
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B
(19,7,25)
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C
(7,19,25)
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D
(5,12,13)
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Solution

The correct option is D (7,19,25)
b+c=11 λ,c+a=12λ,a=b=13λ
a=7λ,b=5λ,c=5λ
(using cosine formula )
cosA=15,cosB=1935,cosC=57
α:β:γ7:19:25

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