Given b - c11 - c - a12 - a - b13 for a - ABC with usual notation- If cos A- - cos B- - cos C- then the ordered triad - - - has a value-

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Cosine Rule

Given b + c...

Question

Given $\frac{b + c}{11} = \frac{c + a}{12} = \frac{a + b}{13}$ for a $Δ A B C$ with usual notation. If $\frac{c o s A}{α} = \frac{c o s B}{β} = \frac{c o s C}{γ}$ , then the ordered triad $(α, β, γ)$ has a value:-

(3, 4, 5)

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(19, 7, 25)

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(7, 19, 25)

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(5, 12, 13)

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Solution

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Similar questions

\frac{b + c}{11} = \frac{c + a}{12} = \frac{a + b}{13}

Δ A B C

\frac{cos A}{α} = \frac{cos B}{β} = \frac{cos C}{γ}

(α, β, γ)

α, β, γ

Δ A B C

\frac{cos A}{α} + \frac{cos B}{β} + \frac{cos C}{γ} =

△ A B C, \frac{b + c}{11} = \frac{c + a}{12} = \frac{a + b}{13}

\frac{cos A}{7} = \frac{cos B}{19} = \frac{cos C}{25}

α, β, γ

Δ A B C

\frac{α^{- 2} + β^{- 2} + γ^{- 2}}{cot A + cot B + cot C} =

\sum (\frac{A}{B}) = 1,

cos (α - β) + cos (β - γ) + cos (γ - α)

sin (α - β) + sin (β - γ) + sin (γ - α)

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