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Rate of Reaction

Given A⇋ B....

Question

Given $A ⇋ B$ . $K_{f}$ is the equilibrium constant and $K_{b}$ is the equilibrium constant for backward reaction. Find the equilibrium constant $K$ .

A

K_{f} / K_{b}

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B

K_{b} / K_{f}

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C

K_{b} \times K_{f}

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D

K_{b} + K_{f}

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Solution

The correct option is B $K_{f} / K_{b}$
Equilibrium constant ; $K_{c} = \frac{K_{f}}{K_{b}}$

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