Given, log102=0.3010,log103=0.4771. The number of zeros after the decimal in 3−100 are
A
140
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B
47
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C
12
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D
none of these
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Solution
The correct option is A47 Let y=3−100 Take log on both side on base 10, log10y=−100log103=−100×.4771=−47.71 Hence, number of zeros after decimal is 47.