Given log10x-2a then 10a in terms of x is -x-If true enter 1 else 0-

nbsp;log _ 10 x = 2a x = 10 ^ 2a Taking root √( x ) = 10 ^ a nbsp; ...

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Properties of Iota

Given log10...

Question

Given ${log}_{10} x = 2 a$ then $10^{a}$ in terms of $x$ is $\sqrt{x}$ .If true enter 1 else 0.

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Solution

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{log}_{10} x = 2 a

{log}_{10} y = \frac{b}{2}

10^{a}

x

\sqrt{x}

{log}_{10} x = a

{log}_{10} y = b

10^{a - 1}

x

3^{2 X} - 3^{X + 1} - 3^{X - 1} + 1 = 0,

x = 0, - 1

If $l o g_{10} x = a$ , find the value of $10^{a - 1}$ in terms of x.

{log}_{10} x = a

10^{a - 2}

x

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