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B
−0.26V
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C
0.349V
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D
0.339V
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Solution
The correct option is C0.349V The standard emf of cell is E0cell=E0Fe2+|Fe−E0Cr3+|Cr=−0.42V−(−0.72V)=0.3V The emf of cell is Ecell=E0cell−0.0592nlog[Cr3+]2[Fe2+]3=0.3V−0.05926log[0.1]2[10]3=0.349V.