Given E - lcirc - Cl - 2 - Cl -1-36 - V - E - Cr -3- - Cr -0-74 V Among the following- the strongest reducing agent isA- Mn 2-B- Cl -C- Cr 3-D- Cr

The correct option is D CrE^∘_MnO^ _4/Mn^+2 = 1.51 V ...(i) E^∘_Cl_2/Cl^ = 1.36 V ...(ii) E^∘_Cr_2 O^ 2_7/Cr^+3 = 1.33 V ...(iii) E^∘_Cr^+3/Cr = ...

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Electrochemical Series

Given E ∧ lci...

Question

Given
$E_{C l_{2} / C l^{-}}^{\circ} = 1.36 V, E_{C r^{3 +} / C r}^{\circ} = - 0.74 V E_{C r_{2} O_{7}^{2 -} / C r^{3 +}}^{\circ} = 1.33 V, E_{M n O_{4}^{-} / M n^{2 +}}^{\circ} = 1.51 V$
Among the following, the strongest reducing agent is

C r

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M n^{2 +}

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C r^{3 +}

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C l^{-}

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Solution

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E_{C l_{2} / C l^{-}}^{\circ} = 1.36 V, E_{C r^{3 +} / C r} = - 0.74 V

E_{C r_{2} O_{7}^{2 -} / C r^{3 +}} = 1.33 V, E_{M n O_{4}^{-} / M n^{2 +}}^{\circ} = 1.51 V

E_{C l_{2} / C l^{-}}^{\circ} = 1.36 V, E_{C r^{3 +} / C r}^{\circ} = - 0.74 V E_{C r_{2} O_{7}^{2 -} / C r^{3 +}}^{\circ} = 1.33 V, E_{M n O_{4}^{-} / M n^{2 +}}^{\circ} = 1.51 V

E_{C r^{(} 3 +) / C r}^{0} = - 0.74 V; E_{M n O_{4}^{-} / M n^{2 +}}^{0} = 1.51 V

E_{C r_{2} O_{7}^{2 -} / C r^{3 +}}^{0} = 1.33 V; E_{C l / C l^{-}}^{0} = 1.36 V

E_{C r^{(} 3 +) / C r}^{0} = - 0.74 V; E_{M n O_{4}^{-} / M n^{2 +}}^{0} = 1.51 V

E_{C r_{2} O_{7}^{2 -} / C r^{3 +}}^{0} = 1.33 V; E_{C l / C l^{-}}^{0} = 1.36 V

E_{C l_{2} / C l^{-}}^{\circ} = 1.36 V, E_{C r^{3 +} / C r} = - 0.74 V

E_{C r_{2} O_{7}^{2 -} / C r^{3 +}} = 1.33 V, E_{M n O_{4}^{-} / M n^{2 +}}^{\circ} = 1.51 V

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