Given E-circ-frac Cr -3- Cr -0-72 V 1E -frac Fe -2- Fe -0-42 V JThe potential for the cell Cr - Cr 3-0-1 M F e 2-0-01 M - Fe isA- -0-339 VB- -0-26 VC- 0-26 VD- 0-339 V

The correct option is C 0.26 VE^0_cell=0.72 0.72 =0.3 E_cell=0.3 0.0591/6 log 0.1^2/0.01^3 = 0.3 0.1 × 4 = 0.3 – 0.04 = 0.26 ...

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Simple Circuit

Given E∧circ-...

Question

Given $E_{\frac{C r^{3 +}}{C r}}^{\circ} = - 0.72 V E_{\frac{F e^{2 +}}{F e}}^{\circ} = - 0.42 V$
The potential for the cell
$\frac{C r}{C r^{3 +}} (0.1 M) | | F e^{2 +} (0.01 M) | F e i s$

-0.339 V

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-0.26 V

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0.26 V

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0.339 V

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Solution

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Similar questions

E_{C r^{3 +} / C r}^{\circ} = - 0.72, E_{F e^{2 +} / F e}^{\circ} = - 0.42 V

C r | C r^{3 +} (0.1 M) | | F e^{2 +} (0.01 M) | F e

E_{C r^{3 +} / C r}^{\circ} = - 0.72 V, E_{F e^{2 +} / F e}^{\circ} = - 0.42 V

C r | C r^{3 +} (0.1 M) | | F e^{2 +} (0.01 M) | F e

Given, $E_{C r^{3 +} / C r}^{0} = - 0.72 V, E_{F e^{2 +} / F e}^{0} = - 0.42 V$

The potential for the cell

C r | C r^{3 +} (0.1 M) | | F e^{2 +} (10.0 M) | F e

C r | C r^{3 +} (0.1 M) | | F e^{2 +} (0.01 M) | F e

E_{C r^{3 +} / C r}^{\circ} = - 0.75 v o l t; E_{F e^{2 +} / F e}^{\circ} = - 0.45 v o l t)

E_{C r^{3 +} |}^{o}

_{Cr}

= - 0.72 V, E_{F e^{2 +} | F e}^{o} = - 0.42

| C r^{3 +} (0.1 M) ∥ F e^{2 +} (0.01 M) |

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