Given, E0Cr(3+)/Cr=−0.74V;E0MnO−4/Mn2+=1.51V E0Cr2O2−7/Cr3+=1.33V;E0Cl/Cl−=1.36V Based on the data given above strongest oxidising agent will be
A
Cl−
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B
Cr3+
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C
Mn2+
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D
MnO−4
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Solution
The correct option is DMnO−4 Higher the standard reduction potential, better is oxidising agent. Among the given E0MnO−4/Mn2+ is highest, hence MnO−4 is the strongest oxidising agent.