Given, $E_{C r^{(} 3 +) / C r}^{0} = - 0.74 V; E_{M n O_{4}^{-} / M n^{2 +}}^{0} = 1.51 V$
$E_{C r_{2} O_{7}^{2 -} / C r^{3 +}}^{0} = 1.33 V; E_{C l / C l^{-}}^{0} = 1.36 V$
Based on the data given above strongest oxidising agent will be

C l^{-}

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C r^{3 +}

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M n^{2 +}

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M n O_{4}^{-}

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Solution

The correct option is D $M n O_{4}^{-}$
Higher the standard reduction potential, better is oxidising agent. Among the given $E_{M n O_{4}^{-} / M n^{2 +}}^{0}$ is highest, hence $M n O_{4}^{-}$ is the strongest oxidising agent.

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