Question

Given, $E_{C{r}^{(}3+)/Cr}^0=-0.74V;E_{Mn{O}_4^{-}/M{n}^{2+}}^0=1.51V$
$E_{C{r}_2{O}_7^{2-}/C{r}^{3+}}^0=1.33V;E_{Cl/C{l}^{-}}^0=1.36V$
Based on the data given above strongest oxidising agent will be

• A. $C{l}^{-}$
• B. $C{r}^{3+}$
• C. $M{n}^{2+}$
• D. $Mn{O}_4^{-}$

Answer 1

The correct option is D $Mn{O}_4^{-}$

Higher the standard reduction potential, better is oxidising agent. Among the given $E_{Mn{O}_4^{-}/M{n}^{2+}}^0$ is highest, hence $Mn{O}_4^{-}$ is the strongest oxidising agent.