Question

Given, $E_{C{r}^{3+}/Cr}^0=-0.74V;E_{Mn{O}_4^{-}/M{n}^{2+}}^0=1.51V,E_{C{r}_2{O}_7^{2-}/C{r}^{3+}}^0=1.33V;E_{Cl/C{l}^{-}}=1.36V$.
Based on the data given above, strongest oxidising agent will be:

• A. $C{r}^{3+}$
• B. $M{n}^{2+}$
• C. $Mn{O}_4{}^{-}$
• D. $C{l}^{-}$

Answer 1

The correct option is C $Mn{O}_4{}^{-}$

A strong oxidizing agent has more tendency to get reduced itself. The given $E^{\circ }$ values are reduction potentials. Here, higher the value, more is the tendency to get reduced.

Therefore, $Mn{O}_4^{-}$ is the strongest oxidizing agent.