Question

Given : ED = EC

then AB + AD > BC.
If the above statement is true then mention answer as 1, else mention 0 if false

Answer 1

In $△ABD$, we have sum of two sides > third
side
$=>AB+AD>BD$ OR

$=>AB+AD>BE+ED--\left(1\right)$
Also, in $△BCE$, we have sum of two sides > third side
$=>EB+EC>BC$ ---- (2)
Adding equations $1,2$ we get
$=>AB+AD+EB+EC>BE+ED+BC$
$=>AB+AD+EC>ED+BC$

But $EC=ED$

Hence, $AB+AD>BC$