Given $f (x) = 4 x + 2$ . Find $f (a + 1)$ when $a = 2$

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Solution

Given, $f (x) = 4 x + 2$
To find: $f (a + 1)$ when $a = 2$
Therefore, $f (a + 1) = 4 (a + 1) + 2$
$= 4 a + 4 + 2$
$= 4 a + 6$
For $a = 2$ , $f (a + 1) = 4 a + 6$
$= 4 (2) + 6$
$= 14$

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