Given- fx - log 1-x-1-x and gx -3x-x3-1-3x2 then fog x equals

(fog)(x)=f(g(x))=f ( 3x+x^3/1+3x^2 ) =log 1+3x^2+3x+x^3/1+3x^2 3x x^3 =log (1+x)^3/(1 x)^3=3 f(x) ...

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Composite Function

Given, fx = l...

Question

Given, f(x) = $l o g \frac{1 + x}{1 - x}$ and g(x) $= \frac{3 x + x^{3}}{1 + 3 x^{2}}$ then (fog) (x) equals

-f(x)

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3f(x)

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[f (x)]^{3}

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None of these

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Solution

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Similar questions

f (x) = log (\frac{1 + x}{1 - x})

g (x) = \frac{3 x + x^{3}}{1 + 3 x^{2}}, f o g (x)

f (x) = l o g (\frac{1 + x}{1 - x})

g (x) = \frac{3 x + x^{3}}{1 + 3 x^{2}}

\frac{d}{d x} (f (g (x)))

If $f (x) = l o g (\frac{1 + x}{1 - x})$ and $g (x) = \frac{3 x + x^{3}}{1 + 3 x^{2}}$ , then f(g(x)) is equal to

f (x) = log (\frac{1 + x}{1 - x})

g (x) = \frac{3 x + x^{3}}{1 + 3 x^{2}}

(f (g (x))))

f (x) = l o g (\frac{1 + x}{1 - x}) a n d g (x) = \frac{3 x + x^{3}}{1 + 3 x^{2}}

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